Kirkman Triple Calculator

15 schoolgirls, 7 days

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About Kirkman Triple Calculator

A Kirkman triple calculator for the famous schoolgirl problem: arrange 15 girls in groups of 3 for 7 days so no two girls share a group twice. This is a resolvable (15,3,1)-BIBD with 35 triples in 7 parallel classes. Client-side.

Kirkman Triple Calculator Features

  • 7-day schedule
  • Parallel classes
  • Pair verification
  • Resolvable STS
  • Automorphisms
Kirkman's schoolgirl problem (1850): 15 girls walk in groups of 3 for 7 days. No pair walks together twice. Solution: partition 35 triples of S(2,3,15) into 7 parallel classes (each covering all 15 girls). 7 non-isomorphic solutions exist.

How to Use

View the 7-day schedule:

  • Days: 5 groups of 3
  • Pairs: All 105 covered
  • Verify: No repeats

History

Thomas Kirkman posed this in 1850, before Steiner systems were defined! Arthur Cayley and others worked on it. The complete classification of solutions came much later. It's one of the most famous problems in combinatorics, inspiring centuries of design theory work.

Generalization

Resolvable (v,3,1)-BIBD: exists iff v≡3(mod6). For v=9: resolvable S(2,3,9)=AG(2,3). For v=15: Kirkman. For v=21: multiple solutions. Ray-Chaudhuri-Wilson theorem guarantees existence for all v≡3(mod6).

Step-by-Step Instructions

  1. 1View schedule.
  2. 2Check each day.
  3. 3Verify no pair repeats.
  4. 4Count all pairs.
  5. 5Explore solutions.

Kirkman Triple Calculator — Frequently Asked Questions

How many solutions exist?+

7 non-isomorphic resolutions of S(2,3,15). With labelings, there are 7×15!/(automorphism group size) total labeled solutions. The 7 solutions were completely classified in the 20th century using sophisticated algebraic and computational methods.

Why is this problem famous?+

It was one of the first problems to combine combinatorics with group theory (automorphisms). It led to the development of design theory and inspired research that continues today. It also shows how simple-sounding problems can be mathematically deep.

Can it be solved for other numbers?+

Resolvable Steiner triples exist for all v≡3(mod6): v=3,9,15,21,27... For v=3: trivial (1 day). For v=9: 12 triples in 4 days. The general construction uses recursive methods and finite geometry.

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