Graph Reconstruction Checker

vertex-deleted deck

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About Graph Reconstruction Checker

A graph reconstruction checker exploring Kelly-Ulam Reconstruction Conjecture: every graph with n≥3 is determined by its deck (multiset of vertex-deleted subgraphs). Verified for n≤13. Kelly's lemma: subgraph counts reconstructible. Client-side.

Graph Reconstruction Checker Features

  • Deck display
  • Reconstruction
  • Kelly lemma
  • Edge count
  • Common graphs
Reconstruction Conjecture (Kelly-Ulam, 1942): every graph with n≥3 vertices is determined (up to isomorphism) by its deck — the multiset of n graphs obtained by deleting each vertex. One of the oldest open problems in graph theory!

How to Use

Select graph:

  • Deck: n cards (vertex-deleted)
  • Reconstruct: Recover G
  • Invariants: From deck

Kelly's Lemma

The number of times any graph H appears as subgraph of G is determined by the deck. So |E|, degree sequence, number of triangles, etc. are all reconstructible. The conjecture: the entire graph is reconstructible too.

Current Status

Verified for n ≤ 13 (McKay, 1997). Proven for: regular graphs, trees, disconnected graphs, planar graphs, outerplanar. Still open in general after 80+ years! Edge reconstruction conjecture: also open (n≥4).

Step-by-Step Instructions

  1. 1Select graph.
  2. 2Generate deck.
  3. 3Extract invariants.
  4. 4Attempt reconstruction.
  5. 5Verify uniqueness.

Graph Reconstruction Checker — Frequently Asked Questions

What's a deck?+

The deck of G is the multiset {G-v₁, G-v₂, ..., G-vₙ}. Each 'card' is the graph obtained by deleting one vertex. The conjecture: the deck uniquely determines G (up to isomorphism) when n≥3.

Why n≥3?+

K₁ and the empty graph on 1 vertex have the same deck (empty). K₂ and 2K₁ have the same deck ({K₁, K₁}). So n≤2 fails. For n≥3, no counterexample has been found in 80+ years.

What about edge reconstruction?+

Edge Reconstruction Conjecture: G (n≥4) is determined by its edge-deleted subgraphs {G-e : e∈E}. Also open! Proven for: n≥edges/2, dense graphs, many special classes. Harder than vertex version.

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